Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review: 10a



Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, then, \begin{array}{l} (3x-1)^2 \\\\ =(3x)^2+2(3x)(-1)+(-1)^2 \\\\ =9x^2-6x+1 .\end{array}
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