Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review: 21c

Answer

$\sqrt[6] 72$

Work Step by Step

$\sqrt[3] 3 \times \sqrt2=3^{\frac{1}{3}}\times 2^{\frac{1}{2}}=3^{\frac{2}{6}}\times 2^{\frac{3}{6}}=(3^{2}2^{3})^{\frac{1}{6}}=(9\times8)^{\frac{1}{6}}=72^{\frac{1}{6}}=\sqrt[6] 72$
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