## Intermediate Algebra (6th Edition)

$k=\frac{1}{24}$, $y=\frac{1}{24}x$
We know that the direct variation equation is in the form $y=kx$ (where k is the constant of variation). Therefore, we can plug in the given values to find the value of k. $\frac{1}{2}=12k$ Divide both sides by 12. $k=\frac{1}{24}$ So the direct variation equation is $y=\frac{1}{24}x$.