Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review: 14a

Answer

$\dfrac{2a}{a-1}$

Work Step by Step

The expression $ \dfrac{\dfrac{a}{5}}{\dfrac{a-1}{10}} $ simplifies to \begin{array}{l} \dfrac{a}{5}\div\dfrac{a-1}{10} \\\\= \dfrac{a}{5}\cdot\dfrac{10}{a-1} \\\\= \dfrac{a}{5}\cdot\dfrac{5\cdot2}{a-1} \\\\= \dfrac{2a}{a-1} .\end{array}
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