Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set: 68

Answer

$a=\dfrac{25}{7}$

Work Step by Step

Using properties of equality, the solution to the given expression, $ -4(a+1)-3a=-7(2a-3) $, is \begin{array}{l} -4a-4-3a=-14a+21 \\\\ -7a+14a=21+4 \\\\ 7a=25 \\\\ a=\dfrac{25}{7} .\end{array}
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