## Intermediate Algebra (6th Edition)

1. Factor the expression. $x^{2}$ - 2x - 15 = (x - 5)(x + 3) 2. Apply the zero factor property. a) x -5 = 0 b) x + 3 = 0 3. Solve each equation. a) x = 5 b) x = -3 The solutions are {-3, 5}.