## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set: 61

#### Answer

$x=\left\{ -\dfrac{1}{3},0 \right\}$

#### Work Step by Step

The factored form of the given expression, $3x^2=-x$, is \begin{array}{l} 3x^2+x=0 \\\\ x(3x+1)=0 .\end{array} Equating each factor to zero, then \begin{array}{l} x=0 ,\text{ OR}\\\\ 3x+1=0 \\ 3x=0-1 \\ 3x=-1 \\ x=-\dfrac{1}{3} .\end{array} Hence, $x=\left\{ -\dfrac{1}{3},0 \right\}$.

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