## Intermediate Algebra (6th Edition)

1. Rearrange expression to equal zero. $m^{3}$ = $m^{2}$ + 12m $m^{3}$ - $m^{2}$ - 12m = 0 2. Factor the expression. m($m^{2}$ - m - 12) m(m + 3)(m - 4) 3. Apply the zero factor property. a) m = 0 b) m + 3 = 0 c) m - 4 = 0 4. Solve each linear equation. a) m = 0 b) m = -3 c) m = 4 The solutions are {-3, 0, 4}.