Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set: 28

Answer

{-3, 0, 4}

Work Step by Step

1. Rearrange expression to equal zero. $m^{3}$ = $m^{2}$ + 12m $m^{3}$ - $m^{2}$ - 12m = 0 2. Factor the expression. m($m^{2}$ - m - 12) m(m + 3)(m - 4) 3. Apply the zero factor property. a) m = 0 b) m + 3 = 0 c) m - 4 = 0 4. Solve each linear equation. a) m = 0 b) m = -3 c) m = 4 The solutions are {-3, 0, 4}.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.