Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set: 25

Answer

{-3, 0, 3}

Work Step by Step

1. Rearrange expression to equal zero. $y^{3}$ = 9y $y^{3}$ - 9y = 0 2. Factor the expression. y($y^{2}$ - 9) y(y + 3)(y - 3) 3. Apply the zero factor property. a) y = 0 b) y + 3 = 0 c) y - 3 = 0 4. Solve each linear equation. a) y = 0 b) y = -3 c) y = 3 The solutions are {-3, 0, 3}.
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