Answer
$\frac{c^{2}}{20}$ - $\frac{c}{4}$ + $\frac{1}{5}$ = 0
c = 4 , 1
Work Step by Step
Directions: Solve each equation.
$\frac{c^{2}}{20}$ - $\frac{c}{4}$ + $\frac{1}{5}$ = 0
$\frac{c^{2}}{20}$ - $\frac{5c}{20}$ + $\frac{4}{20}$ = $\frac{0}{20}$
Multiply each fraction to get a common denominator of 20
$c^{2}$-5c+4=0
All parts of equation are over 20, therefore, you can rewrite the equation without the denominator
(c-4)(c-1)=0
Factor
c=4,1
Find values that make new equation true. c-4=0 and c-1=0, so c=4 and 1.
