Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review: 62

Answer

$-12a^{2}b^{5}-28a^{2}b^{3}-4ab^{2}$

Work Step by Step

$-4ab^{2}(3ab^{3}+7ab+1)$ Distribute the $-4ab^{2}$. $-4ab^{2}(3ab^{3})-4ab^{2}(7ab)-4ab^{2}(1)$ Simplify. $-12a^{2}b^{5}-28a^{2}b^{3}-4ab^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.