Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review: 78

Answer

$9x^{2a}-16$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ of the product of the difference of two squares, then, \begin{array}{l} (3x^a-4)(3x^a+4) \\= (3x^a)^2-(4)^2 \\= 9x^{2a}-16 .\end{array}
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