Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review: 48

Answer

4$x^{3}$ + 4$x^{2}$ + 16xy - 9x + 18

Work Step by Step

(9xy + 4$x^{2}$ + 18) + (7xy - 4$x^{3}$ - 9x) = -4$x^{3}$ + 4$x^{2}$ + (9xy + 7xy) - 9x + 18 = 4$x^{3}$ + 4$x^{2}$ + 16xy - 9x + 18
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