Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review: 68

Answer

$x^2+\dfrac{1}{3}x-\dfrac{2}{9}$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL Method, then, \begin{array}{l} \left( x-\dfrac{1}{3} \right)\left( x+\dfrac{2}{3} \right) \\\\= x^2+\dfrac{2}{3}x-\dfrac{1}{3}x-\dfrac{2}{9} \\\\= x^2+\dfrac{1}{3}x-\dfrac{2}{9} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.