Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review: 72

Answer

$16x^{2}+72x+81$

Work Step by Step

$(4x+9)^{2}$ Special product: $a^{2}+2ab+b^{2}$ Substitute: $a=4x$ and $b=9$ $(4x)^{2}+2(4x)(9)+(9)^{2}$ Simplify $16x^{2}+72x+81$
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