## Intermediate Algebra (6th Edition)

8$x^{2}$(2x - 3)
The GCF of 16 and 24 is 8, and the GCF of $x^{3}$ and $x^{2}$ is $x^{2}$. Therefore, the GCF is 8$x^{2}$. Then factor out the GCF by dividing each figure to get 8$x^{2}$(2x - 3).