Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Cumulative Review - Page 334: 39c

Answer

$\dfrac{49}{4}$

Work Step by Step

Using laws of exponents, then, \begin{array}{l} \left( \dfrac{2}{7} \right)^{-2} \\\\= \left( \dfrac{7}{2} \right)^{2} \\\\= \dfrac{49}{4} .\end{array}
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