Answer
$f(x)=\dfrac{1}{2}x+5$
Work Step by Step
Using $y-y_1=m(x-x_1)$ or the Point-Slope Form of linear equations, the equation of the line with the given conditions,
\begin{array}{l}\require{cancel}
y_1=5
,\\x_1=0
,\\m=\dfrac{1}{2}
,\end{array}
is
\begin{array}{l}\require{cancel}
y-y_1=m(x-x_1)
\\\\
y-5=\dfrac{1}{2}(x-0)
\\\\
y-5=\dfrac{1}{2}x
\\\\
y=\dfrac{1}{2}x+5
.\end{array}
In function notation, the equation above is equivalent to
\begin{array}{l}\require{cancel}
f(x)=\dfrac{1}{2}x+5
.\end{array}
