Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Cumulative Review - Page 334: 39d

Answer

$\dfrac{y^{16}}{25x^{5}}$

Work Step by Step

Using laws of exponents, then, \begin{array}{l} \dfrac{5^{-2}x^{-3}y^{11}}{x^2y^{-5}} \\\\= \dfrac{x^{-3-2}y^{11-(-5)}}{5^{2}} \\\\= \dfrac{x^{-5}y^{16}}{25} \\\\= \dfrac{y^{16}}{25x^{5}} .\end{array}
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