Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Cumulative Review: 44b

Answer

$-6a^{5}b^{3}c^{4}$

Work Step by Step

$(6a^{3}b^{2})(-a^{2}bc^{4})$ $= (-1)(6) \times a^{3} \times a^{2} \times b^{2} \times b \times c^{4}$ [Using $a^{m} \times a^{n} = a^{m+n}$] $ = -6 a^{3+2} \times b^{2+1} \times c^{4}$ $= -6a^{5}b^{3}c^{4}$
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