Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Cumulative Review - Page 334: 40b

Answer

$\dfrac{1}{a^4}$

Work Step by Step

Using laws of exponents, then, \begin{array}{l} \left( \dfrac{a^{-6}}{a^{-8}} \right)^{-2} \\\\= \left( a^{-6-(-8)} \right)^{-2} \\\\= \left( a^{2} \right)^{-2} \\\\= a^{-4} \\\\= \dfrac{1}{a^4} .\end{array}
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