Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Cumulative Review - Page 334: 39b

Answer

$x^{9}$

Work Step by Step

Using laws of exponents, then, \begin{array}{l} \left( \dfrac{x^{-5}}{x^{-2}} \right)^{-3} \\\\= \left( x^{-5-(-2)} \right)^{-3} \\\\= \left( x^{-3} \right)^{-3} \\\\= x^{-3(-3)} \\\\= x^{9} .\end{array}
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