Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Review - Page 667: 15

Answer

$a_{20}=-83$

Work Step by Step

Using $a_n=a_1+(n-1)d$ then, \begin{array}{l} a_{20}=12+(20-1)(-5)\\ a_{20}=12-95\\ a_{20}=-83 .\end{array}
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