Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Review - Page 667: 13

Answer

$a_{13}=43$

Work Step by Step

Using $a_n=a_1+(n-1)d$ then, \begin{array}{l} a_{13}=-5+(13-1)4\\ a_{13}=-5+48\\ a_{13}=43 .\end{array}
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