Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Review - Page 667: 12

Answer

$\left\{ 12,10.5,9,7.5,6 \right\} $

Work Step by Step

With $a_1=12$ and $d=-1.5$, then, \begin{array}{l} a_2=a_1+d\\ a_2=12+(-1.5)\\ a_2=10.5 ,\\\\ a_3=a_2+d\\ a_3=10.5+(-1.5)\\ a_3=9 ,\\\\ a_4=a_3+d\\ a_4=9+(-1.5)\\ a_4=7.5 ,\\\\ a_5=a_4+d\\ a_5=7.5+(-1.5)\\ a_5=6 \end{array} Hence, the first five terms are $ \left\{ 12,10.5,9,7.5,6 \right\} .$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.