## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 11 - Review: 2

#### Answer

$3, 8, 15, 24, 35$

#### Work Step by Step

We find the first $5$ terms by plugging in $1, 2, 3, 4$, and $5$ in for $n$ $a_1 = (1)^2 + 2(1)= 3$ $a_2 = (2)^2 + 2(2)= 8$ $a_3 = (3)^2 + 2(3)= 15$ $a_4 = (4)^2 + 2(4)= 24$ $a_5 = (5)^2 + 2(5)= 35$

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