## Intermediate Algebra (6th Edition)

$-3, -12, -27, -48, -75$
We find the first $5$ terms by plugging in $1, 2, 3, 4$, and $5$ in for $n$ $a_1 = -3(1)2 = -3$ $a_2 = -3(2)^2 = -12$ $a_3 = -3(3)^2 = -27$ $a_4 = -3(4)^2 = -48$ $a_5 = -3(5)^2 = -75$