Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 8 - Summary Exercises - Applying Methods for Solving Quadratic Equations - Page 531: 27

Answer

$\left\{-4,9\right\}$

Work Step by Step

Using factoring of trinomials, the given equation, $ x^2-5x-36=0 ,$ is equivalent to \begin{align*} (x-9)(x+4)&=0 .\end{align*} Equating each factor to zero (Zero Product Property) and solving for the variable, then \begin{array}{l|r} x-9=0 & x+4=0 \\ x=9 & x=-4 .\end{array} Hence, the solution set of the equation $ x^2-5x-36=0 $ is $\left\{-4,9\right\}$.
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