Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 8 - Summary Exercises - Applying Methods for Solving Quadratic Equations - Page 531: 25

Answer

$\left\{-6\sqrt{2},6\sqrt{2}\right\}$

Work Step by Step

In the form $x^2=c,$ the given equation, $ r^2-72=0 ,$ is equivalent to \begin{align*} r^2=72 .\end{align*} Taking the square root of both sides (Square Root Property), the equation above is equivalent to \begin{align*} r&=\pm\sqrt{72} \\&= \pm\sqrt{36\cdot2} \\&= \pm\sqrt{36}\cdot\sqrt{2} \\&= \pm6\sqrt{2} .\end{align*} Hence, the solution set of the equation $ r^2-72=0 $ is $\left\{-6\sqrt{2},6\sqrt{2}\right\}$.
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