Answer
$6k\sqrt 2$
Work Step by Step
$\sqrt (72k^{2})=\sqrt (36\times k^{2}\times2)=\sqrt 36\times\sqrt k^{2}\times\sqrt 2=6k\sqrt 2$
We know that $\sqrt 36=6$, because $6^{2}=36$.
We know that $\sqrt k^{2}=k$, because $(k)^{2}=k^{2}$.
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 7 - Section 7.3 - Simplifying Radicals, the Distance Formula, and Circles - 7.3 Exercises - Page 460: 69
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