Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.3 - Simplifying Radicals, the Distance Formula, and Circles - 7.3 Exercises: 126

Answer

$13 \text{ units}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Use the Distance Formula to find the distance between the given points $\left( -2.9,18.2 \right)$ and $\left( 2.1,6.2 \right)$. $\bf{\text{Solution Details:}}$ With the given points, then $x_1= -2.9 ,$ $x_2= 2.1 ,$ $y_1= 18.2 ,$ and $y_2= 6.2 .$ Using the Distance Formula which is given by $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2} ,$ then \begin{array}{l}\require{cancel} d=\sqrt{(-2.9-2.1)^2+(18.2-6.2)^2} \\\\ d=\sqrt{(-5)^2+(12)^2} \\\\ d=\sqrt{25+144} \\\\ d=\sqrt{169} \\\\ d=\sqrt{(13)^2} \\\\ d=13 .\end{array} Hence, the distance is $ 13 \text{ units} .$
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