Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.3 - Simplifying Radicals, the Distance Formula, and Circles - 7.3 Exercises: 68

Answer

$3\sqrt[6] 2$

Work Step by Step

$\sqrt[6] 1458=\sqrt[6] (729\times2)=\sqrt[6] 729\times\sqrt[6] 2=3\sqrt[6] 2$ We know that $\sqrt[6] 729=3$, because $3^{6}=729$.
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