Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.3 - Simplifying Radicals, the Distance Formula, and Circles - 7.3 Exercises: 64

Answer

$2\sqrt[5] 4$

Work Step by Step

$\sqrt[5] 128=\sqrt[5] (32\times4)=\sqrt[5] 32\times\sqrt[5] 4=2\sqrt[5] 4$ We know that $\sqrt[5] 32=2$, because $2^{5}=32$.
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