#### Answer

3

#### Work Step by Step

The product rule for radicals tells us that $\sqrt[n] a\times\sqrt[n] b=\sqrt[n] ab$ (when $\sqrt[n] a$ and $\sqrt[n] b$ are real numbers and $n$ is a natural number). That is, the product of two nth roots is the nth root of the product.
Therefore, $\sqrt 3\times\sqrt 3=\sqrt (3\times3)=\sqrt 9=3$.
We know that $\sqrt 9=3$, because $3^{2}=9$.