Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Section 7.3 - Simplifying Radicals, the Distance Formula, and Circles - 7.3 Exercises: 104

Answer

$\sqrt 2$

Work Step by Step

We know from the radical form of $a^{\frac{m}{n}}$ that $a^{\frac{m}{n}}=\sqrt[n] a^{m}$ (where the indicated roots are real numbers). Therefore, $\sqrt[6] 8=\sqrt[6] 2^{3}=2^{\frac{3}{6}}=2^{\frac{1}{2}}=\sqrt 2$.
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