## Intermediate Algebra (12th Edition)

$\sqrt{37} \text{ units}$
$\bf{\text{Solution Outline:}}$ Use the Distance Formula to find the distance between the given points $\left( -1,2 \right)$ and $\left( 5,3 \right)$. $\bf{\text{Solution Details:}}$ With the given points, then $x_1= -1 ,$ $x_2= 5 ,$ $y_1= 2 ,$ and $y_2= 3 .$ Using the Distance Formula which is given by $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2} ,$ then \begin{array}{l}\require{cancel} d=\sqrt{(-1-5)^2+(2-3)^2} \\\\ d=\sqrt{(-6)^2+(-1)^2} \\\\ d=\sqrt{36+1} \\\\ d=\sqrt{37} .\end{array} Hence, the distance is $\sqrt{37} \text{ units} .$