## Intermediate Algebra (12th Edition)

Published by Pearson

# Chapter 7 - Section 7.3 - Simplifying Radicals, the Distance Formula, and Circles - 7.3 Exercises: 125

#### Answer

$5 \text{ units}$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$ Use the Distance Formula to find the distance between the given points $\left( 4.7,2.3 \right)$ and $\left( 1.7,-1.7 \right)$. $\bf{\text{Solution Details:}}$ With the given points, then $x_1= 4.7 ,$ $x_2= 1.7 ,$ $y_1= 2.3 ,$ and $y_2= -1.7 .$ Using the Distance Formula which is given by $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2} ,$ then \begin{array}{l}\require{cancel} d=\sqrt{(4.7-1.7)^2+(2.3-(-1.7))^2} \\\\ d=\sqrt{(4.7-1.7)^2+(2.3+1.7)^2} \\\\ d=\sqrt{(3)^2+(4)^2} \\\\ d=\sqrt{9+16} \\\\ d=\sqrt{25} \\\\ d=\sqrt{(5)^2} \\\\ d=5 .\end{array} Hence, the distance is $5 \text{ units} .$

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