College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises: 54

Answer

(a) 9 (b) $\frac{1}{7}$ (c) $\frac{1}{36}$

Work Step by Step

(a) $3^{2/7}*3^{12/7}=3^{2/7+12/7}=3^{2}=9$ (b) $\frac{7^{2/3}}{7^{5/3}}=7^{2/3-5/3}=\frac{1}{7}$ (c) $(\sqrt[5]{6})^{-10}=(6^{1/5})^{-10}=\frac{1}{36}$
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