College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises: 71

Answer

$x^{\frac{5}{9}}$

Work Step by Step

The exponent of $x$ (which is 5) is lower then the index (9). This means that the radical is already in simplest form. RECALL: $\sqrt[n]{a^m} = a^{\frac{m}{n}}$ Thus, $\sqrt[9]{x^5} = x^{\frac{5}{9}}$
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