College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises - Page 30: 53

Answer

(a) 5 (b) $\sqrt[5]{3}$ (c) 4

Work Step by Step

(a) $5^{2/3}*5^{1/3}=5^{2/3+1/3}=5^{1}=5$ (b) $\frac{3^{3/5}}{3^{2/5}}=3^{3/5-2/5}=\sqrt[5]{3}$ (c) $(\sqrt[3]{4})^{3}=(4^{1/3})^3=4$
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