College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises: 42

Answer

$\sqrt[3]{2}$

Work Step by Step

Factor each radicand so that one of the factors is a perfect cube to obtain: $=\sqrt[3]{27(2)} -\sqrt[3]{8(2)} \\=\sqrt[3]{3^3(2)}-\sqrt[3]{2^3(2)}$ Simplify each radical to obtain: $=3\sqrt[3]{2} - 2\sqrt[3]{2}$ Combine like radicals to obtain: $=(3-2)\sqrt[3]{2} \\=1\cdot \sqrt[3]{2} \\=\sqrt[3]{2}$
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