College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises: 48

Answer

$6\sqrt{x^2+y^2}$

Work Step by Step

Factor the radicand so that one of the factors is a perfect square to obtain: $=\sqrt{36(x^2+y^2)} \\=\sqrt{6^2(x^2+y^2)}$ Simplify the radical to obtain: $=6\sqrt{x^2+y^2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.