College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises: 87

Answer

(a) $\frac{\sqrt{5x}}{5x}$ (b) $\frac{\sqrt{5x}}{5}$ (c) $\frac{x^{2/5}}{x}$

Work Step by Step

(a) $\displaystyle \frac{1}{\sqrt{5x}}=\frac{1}{\sqrt{5x}} \displaystyle \frac{\sqrt{5x}}{\sqrt{5x}}=\frac{\sqrt{5x}}{5x}$ (b)$\displaystyle \sqrt{\frac{x}{5}}=\frac{\sqrt{x}}{\sqrt{5}} \displaystyle=\frac{\sqrt{x}}{\sqrt{5}} \displaystyle \frac{\sqrt{5}}{\sqrt{5}}=\frac{\sqrt{5x}}{5}$ (c) $\displaystyle \sqrt[5]{\frac{1}{x^{3}}}=\frac{1}{x^{3/5}} \displaystyle \frac{x^{2/5}}{x^{2/5}}=\frac{x^{2/5}}{x}$
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