Answer
$\log{96}$
Work Step by Step
RECALL:
(1) $\log_a{(P^n)}=n \cdot \log_a{P}$
(2) $\log_a{(PQ)}= \log_a{P} + \log_a{Q}$
(3) $\log_a{(\frac{P}{Q})}= \log_a{P} - \log_a{Q}$
Use rule (1) above to obtain
$\log{6}+4\log{2}
\\= \log{6} + \log{(2^4)}
\\=\log{6} + \log{16}$
Use rule (2) above to obtain:
$\log{6} + \log{16}
\\= \log{(6\cdot 16)}
\\=\log{96}$
