Answer
$49$
Work Step by Step
RECALL:
(1) $e^{\ln{x}}=x$
(2) $n \cdot \ln{x} = \ln{(x^n)}$
Use rule (2) above to obtain:
$e^{2\ln{7}}=e^{\ln{(7^2)}}$
Use rule (2) above with $x=7^2$ to obtain:
$e^{\ln{(7^2)}}=7^2=49$
Thus,
$e^{2\ln{7}}=49$
