Answer
Domain: $-1\lt x\lt2$
Work Step by Step
We must have that:
$2+x-x^2\gt0$
$2+2x-x-x^2\gt0$
$2(1+x)-x(1+x)\gt0$
$(2-x)(1+x)\gt0$
Both factors must be positive:
$2-x\gt0$
$-x\gt-2$
$x\lt2$
$1+x\gt0$
$x\gt-1$
$-1\lt x\lt2$
Or both factors must be negative:
$2-x\lt0$
$-x\lt-2$
$x\gt2$
$1+x\lt0$
$x\lt-1$
A number can not be greater than 2 and less than -1 at the same time.