College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Concept Check: 50

Answer

$\frac{1}{3}\ln(x^{4}+12)-\ln(x+16)-\frac{1}{2}\ln(x-3)$

Work Step by Step

We expand: $\ln(\frac{\sqrt[3]{x^{4}+12}}{(x+16)\sqrt{x-3}})$ $\ln(x^{4}+12)^{\frac{1}{3}}-[\ln(x+16)+\ln(x-3)^{\frac{1}{2}}]$ $\frac{1}{3}\ln(x^{4}+12)-[\ln(x+16)+\frac{1}{2}\ln(x-3)]$ $\frac{1}{3}\ln(x^{4}+12)-\ln(x+16)-\frac{1}{2}\ln(x-3)$
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