## College Algebra 7th Edition

Domain: $(-\infty,\ \frac{1}{2})$
We are asked to find the domain of: $f(x)=10^{x^{2}}+\log(1-2x)$ We can't take a log of a negative number (or 0), so: $1-2x\gt 0$ $-2x\gt -1$ $x\lt \frac{1}{2}$ Therefore, the domain is: $(-\infty,\ \frac{1}{2})$