Answer
$2$
Work Step by Step
RECALL:
(1) $\log{P} + \log{Q} = \log{(PQ)}, P, Q \gt 0$
(2) $\log{(10^k)} = k$
Use rule (1) above to obtain:
$=\log{(25\cdot4)}
\\=\log{100}$
Note that $100=10^2$.
Thus, the expression above is equivalent to:
$\log{100} = \log{(10^2)}$
Use rule (2) above to obtain:
$\log{(10^2)} = 2$
