College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 1, Equations and Graphs - Section 1.2 - Graphs of Equations in Two Variables; Circles - 1.2 Exercises: 73

Answer

$(x+3)^2+(y-2)^2=25$

Work Step by Step

RECALL: The standard form of a circle whose center is at $(h, k)$ and radius $r$ is $(x--h)^2+(y-k)^2=r^2$. With the center at $(-3, 2)$, then $h=-3$ and $k=2$. The radius is 5 so $r=5$. Thus, the standard form of the given circle's equation of the circle is: $[x-(-3)]^2+(y-2)^2=5^2 \\(x+3)^2+(y-2)^2=25$
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